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Thread: Python: IndentationError: expected an indented block


hi, trying first python program , having little bit of trouble. "indentationerror: expected indented block". tried searching google solution , found not implement them. trying after reading few tutorials , book python. appreciate if indicate me how fix error. thank you.
here code:
if see syntax errors please indicate them me. can see beginner.
code:
#size_calculator.py #!/usr/local/bin/python import time import datetime today = datetime.date.today() print "the date is", today     print('this program calculates perimeter, surface, , volume.') def     selection() :  d = raw_input( 'enter p calculate perimeter, enter v calculate volume, enter s calculate surface, or ctrl+c exit! p/v/s :')      if d == 'p': def perimeter():  while 1:   a= raw_input('enter lenght: ')   b= raw_input('enter width: ')   print('the perimeter is'),a+b   selection   if d == 'v' : volume()   if d == 's' : surface()   if d == 'p' : perimeter()  print('the program exit, thank using it.')  raw_input('press <enter> exit')   if d == 'v': def volume():  while 2:   g= input('enter height: ')    f= input('enter lenght: ')   h= input('enter width: ')   print('the volume '),g*f*h   selection   if d == 'v' : volume()   if d == 's' : surface()   if d == 'p' : perimeter()  print('the program exit, thank using it.')  raw_input('press <enter> exit')   if d == 's': def surface():  while 3:   n= input('enter lenght: ')   m= input('enter width: ')   print('the surface '),n*m   selection   if d == 'v' : volume()   if d == 's' : surface()   if d == 'p' : perimeter()  print('the program exit now, thank using it.')      raw_input('press <enter> exit')
this error output terminal:
code:
cgroza@cgroza-desktop:~/desktop$ python program.py    file "program.py", line 16     def     perimeter():       ^ indentationerror: expected indented block cgroza@cgroza-desktop:~/desktop$ python program.py    file "program.py", line 16     def     perimeter():       ^

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